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47........Noah's Ark....the other witness
Full credit is given for the information below concerning the discovery
of Noah's Ark to Ron Wyatt. Visit his web site and find out about his
many amazing and heroic discoveries. At the end of Ron's material we
will discuss the issue of doomsday as related to the Ark. Here is Ron's
address:
http://www.pilgrimpromo.com/WAR/index.html
1) The "object" you claim is the remains of Noah's Ark is about 515 feet long and 138 feet wide. The Bible says the Ark was 300 cubits long and 50 cubits wide. I always believed that would mean the Ark would have been 450 feet long by 75 feet wide. How do you explain this discrepancy with the Bible?
The royal Egyptian cubit was 20.62 inches. Now, if we consider the Biblical statement that Moses was "learned in all the wisdom of Egypt" - Acts 7:22, as the author of Genesis, he would have been referring to the only cubit he knew. 300 cubits = 515.5 feet. 50 cubits = 85.9 feet. The measurement of the length of the boat, taken in August, 1985 by Maylon Wilson and Baumgardner of Los Alamos Laboratory with sophisticated measurement devices, showed the inside length of the boat to be 515.7 feet! David Fasold's measurement of the same was exactly 515 feet!
The width of 138 feet, (my measurement and also David's) may at first seem to present a problem until we consider it carefully. The boat is splayed. The height given in the Bible is 30 cubits or 51.55 feet.
The width is given as 50 cubits or 85.916 feet. The total of both sides plus the width is 189.016 feet -far too wide. But if the hull of the ship was exactly half the entire height of the boat, and the hull splayed outward, the width would be 137.466 feet! Our later metal detection results confirmed these figures as well as the sub-surface interface radar scans.
The end of Ron Wyatt's material....be sure to see his picture of the Ark.
data 515.5 x12 = 300 x 20.62 = 6186 inches for the length of Ark(6179.5 PI or 6180)
.......therefore................................618.6 in. is the height of ark (617.95 PI or 618)
.......and.........................................1031 in. is the width of the ark (1029.92 PI or 1030)
Data updated for proposed actual length of the Ark as the average of the precise 300 cubits ( 515.5 feet ) and the measurement by David Fasold ( 515 feet ) which average is 515.25 feet. So the following data is very near to the actual size of the Ark as Noah constructed it. .....515.25 ft. x12 (or 299.85 cubits x 20.62) = 6183 inches for the length of the Ark which is equal to
6176.5 p.i. ( the height would be 617.65 p.i. and the width equals 1030.5 p.i. ).
How do these measurements relate to doomsday and to the other pyramidal witness? We know that one inch is one prophetic year (see section 40 on the Great Pyramid of Giza).....
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Just below the Ark position (apx 100 pi) starting at exactly 1162.6 pi there is a row of blocks girding the pyramid which are twice the size of the previous layers (apx 25 previous to 50 pi). This is roughly in line with the top of the Queen's pointed roof and the top of the lower end of the Grand Gallery and is the 35 th course of blocks. This is, in the first place, a confirmation of the designed height of the pyramid as projected to the tip of the missing apex as exactly 5813 pi. The word 'pyramid' means to meter by tens. Now the entrance passage is estimated to be apx 49 ft. above ground level ( not being intact for accurate measurement ). So it is evident that the actual height is 581.3 pi and with the upward addition of the next 581.3 pi you arrive at the base of the 50 inch blocks. Exactly ten of these units brings you to the tip of the pyramid.
[4:7] - The perfect formula height of the pyramid including the missing apex is 5813.2355653763+ PI, calculated from perimeter of base (sidereal socket level) divided by 2 Pi.
[4:221] - Antechamber to King's Chamber: 116.26471 PI length (103.03292 PI is granite), 149.44644 PI high
[4:11] - The estimated height of the capstone is about 103.03+ pyramid inches
My estimate is the 116.26
[14:16] - The length of the Antechamber to the King's Chamber = 1/50th the height of the pyramid
Now, the length of the Antechamber is exactly 116.26 which is exactly 1/10 of the 1162.6 block measurement. Thus the Antechamber is exactly 1/50 th of the height of the pyramid. Now, this same Antechamber contains 103.0 of this distance in the form of the special red granite, and this is 1/10 of the width of the Ark. Note that 103 pi is the basic unit of the Ark. So we begin to see that the Ark fits very nicely with the pyramid. Note that the bottom of the Ark bisects the bottom of the Grand Gallery, and the entire Ark centers across the top of the Grand Gallery.
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The blue triangle................(in the drawing above)
This is the key to the mystery of the relation of the Ark to
the pyramid.
A....this is where the Ark comes to the edge of the pyramid.
B....is the center of the Ark and the pyramid horizontally.
C....This is the third point of the triangle which is a point in
the center of the pyramid at the exact level of the
descending passage where it levels out to enter the pit.
This level is exactly 1162.6 p.i. below the pyramid base
(measured to the apx. center of the passage).
D....is the bottom of the row of extra large blocks (apx 100 pi
beneath the Ark) which is exactly 1162.6 p.i. above the
pyramid base.
...note that the basic unit of the pyramid is 581.3 p.i. (which is five times the 116.26 p.i. length of the antechamber). Now ten of these units form the height of the pyramid at 5813 p.i. Also note that two of these units are below the pyramid base and two of these units are immediately above the base ( the first extends to the pyramid entrance and the second to the bottom of the large row of blocks). There are eight more units to the apex (the missing capstone is 116.26 p.i. high and exactly 1/50 the size of the pyramid).
An interesting side note is that if the top eight units are abitrarily divided into 2 plus 6...then the units line up as 2...6....2....2 (2622) being the date line at the entrance. This would give an arbitary level at 4650 p.i. and I may persue this in the 'math notes' section.
the known distances....
A to B....this is a distance of 3088.25 p.i. (1/2 the Ark)
C to base of pyramid....is 1162.6 p.i.
B to base of pyramid....is 1881 p.i. (1880.9)
(this is composed of the Ark height of 617.65 p.i. plus
the two units mentioned above of 518.3 p.i. each and
the distance from D to the bottom of the Ark which is
100.65 p.i.) ( 1881 plus 3932 equals 5813 )
B to top of pyramid....3932 p.i. (3932.1)
B to C....3043.5 p.i. ( 1880.9 plus 1162.6)
Now we can calculate the distance A to C which will relate the Ark to the pyramid.
A to C....equals the square root of A to B squared plus
B to C squared which is to say....the square
root of 9,537,288.0625 plus 9,262,892.25 which
is the square root of 18,800,180.3125 (notice the
nearness of this to 1881...) which is 4335.917 or
4336 p.i. Now remember that B to C is composed
as shown above of the 1881 p.i. plus the two units
of the pyramid (581.3 each).
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4336 minus 1881 equals 2455...................
the year of the flood.
(see section 11 on the timeline and section 40 for 1 b.c. birth of Christ)
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B to C (3043.5) formed into an equilateral
triangle...and the perimeter measured ( or just
take 3043.5 times 3)....equals 9130.5 which is
the base line of the pyramid which divided by
25 gives the number of royal cubits which equals
the number of days in a year...365.24. Twice the
distance of this baseline divided by the height of
the pyramid equals Pi to 5 decimal places.
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So the Ark mathematically verifies the message of the pyramid which points to doomsday and rapture in 2002. Are you ready? The time is very short now. Does anyone have ears to hear? Please send me an e-mail with your thoughts and any
additional revelations as to volume measurements etc.
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p.s....I will add to this as more is revealed in the section called 'math notes'
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